VCE Maths Methods — Algebra and Equations
Algebraic fluency is the foundation of every other Methods topic. Students who struggle with calculus almost always have gaps in algebra — sign errors, incorrect factoring or missing solutions. This page covers the key algebraic techniques for Units 1–4, with a focus on the exact processes examiners reward in full working.
Key Concepts & Formulas
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Quadratic formula: for ax² + bx + c = 0, x = (−b ± √(b² − 4ac)) / 2a
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Discriminant Δ = b² − 4ac: Δ > 0 two real solutions, Δ = 0 one repeated solution, Δ < 0 no real solutions
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Factoring techniques: difference of squares a² − b² = (a+b)(a−b), perfect square a² ± 2ab + b² = (a ± b)²
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Polynomial factor theorem: (x − a) is a factor of P(x) if and only if P(a) = 0
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Completing the square: x² + bx = (x + b/2)² − (b/2)²
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Simultaneous equations — substitution works when one equation is linear; elimination when coefficients match
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Index laws: aᵐ × aⁿ = aᵐ⁺ⁿ, aᵐ ÷ aⁿ = aᵐ⁻ⁿ, (aᵐ)ⁿ = aᵐⁿ, a⁰ = 1, a⁻ⁿ = 1/aⁿ
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Logarithm laws: log(ab) = log a + log b, log(a/b) = log a − log b, log(aⁿ) = n log a
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Exponential and log inverses: eˡⁿˣ = x and ln(eˣ) = x; aˡᵒᵍₐˣ = x
Practice Questions
5 questionsAttempt each question before reading the hint. These are styled to match VCE exam format.
Q1.Solve 2x² − 5x − 3 = 0 by factoring.
2 marksQ2.Find the values of k for which kx² − 4x + 1 = 0 has exactly one solution.
2 marksShow hint
Set the discriminant equal to zero.
Q3.Given P(x) = x³ − 2x² − 5x + 6, show that (x − 1) is a factor and hence factorise P(x) fully.
3 marksQ4.Solve the simultaneous equations: 3x + 2y = 7 and x² + y = 4.
3 marksQ5.Solve log₂(x + 3) + log₂(x − 1) = 3.
3 marksShow hint
Combine logs first using log(ab) = log a + log b.
Common Mistakes to Avoid
These are the errors that VCE students most frequently make in Algebra and Equations — and that examiners are specifically watching for.
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Only writing one solution to a quadratic when both ± roots are valid
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Sign errors when substituting negative numbers into the quadratic formula — always bracket negatives: (−b)
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Using the factor theorem but not completing the full factorisation into linear factors
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Forgetting to check logarithm solutions are in the valid domain (x must make all log arguments positive)
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