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VCE Units 1–4 · Maths Methods

VCE Maths Methods — Algebra and Equations

Algebraic fluency is the foundation of every other Methods topic. Students who struggle with calculus almost always have gaps in algebra — sign errors, incorrect factoring or missing solutions. This page covers the key algebraic techniques for Units 1–4, with a focus on the exact processes examiners reward in full working.

Key Concepts & Formulas

  • Quadratic formula: for ax² + bx + c = 0, x = (−b ± √(b² − 4ac)) / 2a

  • Discriminant Δ = b² − 4ac: Δ > 0 two real solutions, Δ = 0 one repeated solution, Δ < 0 no real solutions

  • Factoring techniques: difference of squares a² − b² = (a+b)(a−b), perfect square a² ± 2ab + b² = (a ± b)²

  • Polynomial factor theorem: (x − a) is a factor of P(x) if and only if P(a) = 0

  • Completing the square: x² + bx = (x + b/2)² − (b/2)²

  • Simultaneous equations — substitution works when one equation is linear; elimination when coefficients match

  • Index laws: aᵐ × aⁿ = aᵐ⁺ⁿ, aᵐ ÷ aⁿ = aᵐ⁻ⁿ, (aᵐ)ⁿ = aᵐⁿ, a⁰ = 1, a⁻ⁿ = 1/aⁿ

  • Logarithm laws: log(ab) = log a + log b, log(a/b) = log a − log b, log(aⁿ) = n log a

  • Exponential and log inverses: eˡⁿˣ = x and ln(eˣ) = x; aˡᵒᵍₐˣ = x

Practice Questions

5 questions

Attempt each question before reading the hint. These are styled to match VCE exam format.

Q1.Solve 2x² − 5x − 3 = 0 by factoring.

2 marks

Q2.Find the values of k for which kx² − 4x + 1 = 0 has exactly one solution.

2 marks
Show hint

Set the discriminant equal to zero.

Q3.Given P(x) = x³ − 2x² − 5x + 6, show that (x − 1) is a factor and hence factorise P(x) fully.

3 marks

Q4.Solve the simultaneous equations: 3x + 2y = 7 and x² + y = 4.

3 marks

Q5.Solve log₂(x + 3) + log₂(x − 1) = 3.

3 marks
Show hint

Combine logs first using log(ab) = log a + log b.

Common Mistakes to Avoid

These are the errors that VCE students most frequently make in Algebra and Equations — and that examiners are specifically watching for.

  • Only writing one solution to a quadratic when both ± roots are valid

  • Sign errors when substituting negative numbers into the quadratic formula — always bracket negatives: (−b)

  • Using the factor theorem but not completing the full factorisation into linear factors

  • Forgetting to check logarithm solutions are in the valid domain (x must make all log arguments positive)

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